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Stream.zipLatestAll

Open dilame opened this issue 1 year ago • 0 comments

What is the problem this feature would solve?

We have an extremely useful Stream.concatAll and Stream.mergeAll functions, but we don't have the same concept for zipping latest values.

What is the feature you are proposing to solve the problem?

Implement

type ZipLatestAllValues<T extends Array<Stream<unknown, unknown, unknown>>> = { [K in keyof T]: T[K] extends Stream<infer U> ? U : never }
type ZipLatestAllErrors<T extends Array<Stream<unknown, unknown, unknown>>> = T extends Array<Stream<unknown, infer E, unknown>> ? E : never;
type ZipLatestAllContext<T extends Array<Stream<unknown, unknown, unknown>>> = T extends Array<Stream<unknown, unknown, infer R>> ? R : never;

export declare const zipLatestAll: {
    <A extends Array<Stream<unknown, unknown, unknown>>>(...streams: A): Stream<ZipLatestAllValues<A>,  ZipLatestAllErrors<A>, ZipLatestAllContext<A>>;
};

// Stream.Stream<[number, string, boolean], never, never>
const latest = Stream.zipLatestAll(Stream.make(1,2,3), Stream.make('a','b','c'), Stream.make(true,false))

What alternatives have you considered?

No response

dilame avatar May 09 '24 10:05 dilame