Incorrect triggering of PHP0421 warning: The variable '$...' is assigned, but its value is never used

[coderapers]

Hi.

Why when I use assignment to array by just created variable Devsense reports me PHP0421 warning? Variable will be used in next code line.

[jakubmisek]

Thank you for reporting that, it looks like a bug.

[jakubmisek]

Code to reproduce:

$form[0] = $container = new ArrayObject;
$container[1] = 123;

[Ahmedahasssan]

$form[0] = $container = new ArrayObject; $container[1] = 123;

[jakubmisek]

Fixed in the next update (1.47 pre-release or 1.48), thanks!