Use regex to remove all instances of var/ in proc args

[Xander3359]

What this PR does

So basically when you have a proc you need args in it /proc(args...)

You don't need var/arg This runs a regex to replace all instances of var/

You can do this yourself by running the following substitution Search: (^/[\w/][^ \t]+(.*)(var/|, ?var/.*)(.*)) Replace: $1$3