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Extension syntax error

Open ThomasKFitzgerald opened this issue 5 months ago • 4 comments

Terminal window:

PS C:\DevOps\Python\Learning\Databases> sqlite3 SQLite version 3.46.1 2024-08-13 09:16:08 (UTF-16 console I/O) Enter ".help" for usage hints. Connected to a transient in-memory database. Use ".open FILENAME" to reopen on a persistent database. sqlite> .open test.db sqlite> CREATE TABLE investments (coin_id TEXT, currency TEXT, anount REAL); sqlite> .tables investments sqlite> .headers on sqlite> .mode column sqlite> pragma table_info('investments'); cid name type notnull dflt_value pk


0 coin_id TEXT 0 0 1 currency TEXT 0 0 2 anount REAL 0 0 sqlite> INSERT INTO investments VALUES ('bitcoin', 1.0, 'usd'); sqlite> SELECT * FROM investments; coin_id currency anount


bitcoin 1.0 usd sqlite> .exit PS C:\DevOps\Python\Learning\Databases>

This is a new DB.

image

When clicking open database this is the error:
" [9:58:20 AM][vscode-sqlite][INFO] Activating extension vscode-sqlite v0.14.1... [9:58:20 AM][vscode-sqlite][INFO] Extension activated. [10:03:05 AM][vscode-sqlite][ERROR] Failed to open database 'c:\DevOps\Python\Learning\Databases\test.db': Parse error near line 4: no such column: "table" - should this be a string literal in single-quotes? aster WHERE (type="table" OR type="view")
error here ---^ "

ThomasKFitzgerald avatar Sep 10 '24 09:09 ThomasKFitzgerald