Incorrectly parsed `if` condition?

[simonmandlik]

This is from neovim:

if 1 + 1 < 2
end
if 2 > 1 + 1
end

and resulting nodes:

(if_statement) ; [1:1 - 2:3]
 condition: (integer_literal) ; [1:4 - 4]
 (binary_expression) ; [1:6 - 12]
  (unary_expression) ; [1:6 - 8]
   (operator) ; [1:6 - 6]
   (integer_literal) ; [1:8 - 8]
  (operator) ; [1:10 - 10]
  (integer_literal) ; [1:12 - 12]
(if_statement) ; [3:1 - 4:3]
 condition: (binary_expression) ; [3:4 - 12]
  (integer_literal) ; [3:4 - 4]
  (operator) ; [3:6 - 6]
  (binary_expression) ; [3:8 - 12]
   (integer_literal) ; [3:8 - 8]
   (operator) ; [3:10 - 10]
   (integer_literal) ; [3:12 - 12]

Isn't the first one wrong?

[savq]

Yes, this is parsed incorrectly.

Unfortunately, Julia allows omitting the terminator (newline or semicolon) between the condition and the consequent, so an expression like if x y end is syntactically valid. In this case, instead of x and y we have 1 and +1 < 2.