Not able to pass function with parameters to AddFunc()

[pravandkatyare]

I wanted to pass some of the data which is essential for a cron job for execution of internal logic.

Lets take an example as cronInstance.AddFunc( <cronExpression>, func(interface{}, interface{})) which as of now I'm not able to do.

If not this way, please suggest me some alternative to pass data to cron job while it is being added to run.

[obalunenko]

You can wrap it with anonimous function if you want to pass some parameters to it.

cronInstance.AddFunc( <cronExpression>, func(func(interface{}, interface{})))

[electricbubble]

var _ cron.Job = (*tmpJob)(nil)

type tmpJob struct {
	name string
	done chan struct{}
}

func (t *tmpJob) Run() {
	fmt.Println("hi", t.name)
	t.done <- struct{}{}
}

func TestCronJob(t *testing.T) {
	c := cron.New(cron.WithSeconds())
	c.Start()

	job := &tmpJob{
		name: "electricbubble",
		done: make(chan struct{}),
	}
	_, err := c.AddJob("* * * * * *", job)
	if err != nil {
		t.Fatal(err)
	}

	<-job.done
}

[jackcipher]

In actual, AddFunc is just a wrapper for AddJob. AddJob will be invoked finnaly.

So, If u wanna carry some params, u can use AddJob(), as @electricbubble provieds

[yanqiaoyu]

this is how I solve it by using AddFunc

package main

import (
	"log"

	"github.com/robfig/cron/v3"
)

func showName(name string) {
	log.Println("Hi~ My name is", name)
}

func main() {
	c := cron.New(cron.WithSeconds())
	c.AddFunc("*/1 * * * * ?", func() { showName("Johnny Silverhand") })
	c.AddFunc("*/1 * * * * ?", func() { showName("V") })
	c.Start()

	select {}
}