[js] 第46天 写一个使两个整数进行交换的方法（不能使用临时变量）

[haizhilin2013]

第46天 写一个使两个整数进行交换的方法（不能使用临时变量）

[xiangshuo1992]

利用运算符优先级和0* b = a + 0 * (a = b); 利用执行顺序

a = a + b;
b = a - b;
a = a - b;

异或取值

a ^= b;
b ^= a;
a ^= b;

[chwech]

let a = 1, b= 2
[a, b] = [b, a]

[wenyejie]

利用运算符优先级和0* b = a + 0 * (a = b); 利用执行顺序

a = a + b;
b = a - b;
a = a - b;

异或取值

a ^= b;
b ^= a;
a ^= b;

我去这种骚操作, 我只知道一个解构.

[myprelude]

• ES6

let [a,b] = [b,a]  

• ES5

var a = 1,b = 2;
a = b+a;
b = a-b;
a = a-b;

[chenliwen123]

• ES6

let [a,b] = [b,a]  

• ES5

var a = 1,b = 2;
a = b+a;
b = a-b;
a = a-b;

ES 6 这个 优秀

[seho-dev]

不能使用临时变量的是什么意思求解答

[vincent-yan]

1:a ^= b; b ^= a; a ^= b;

2:es6解构 [b,a]=[a,b]

在 2019年9月15日，下午3:13，LAO_SHEN <[email protected]mailto:[email protected]> 写道：

不能使用临时变量的是什么意思求解答

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[zxl-lxz]

let a = 1;
let b = 2;
[a, b] = [b, a];
console.log(a, b); // => 2, 1

[blueRoach]

let a = 1, b = 2 return [a, b] = [b, a]

[Alex-Li2018]

1. 第一种

let b = 1
let c = 2
let tmp
tmp = b
b = c
c = tmp

2. 第二种

let a = 1;
let b = 2;
[a, b] = [b, a];

[smile-2008]

利用运算符优先级和0* b = a + 0 * (a = b); 利用执行顺序

a = a + b;
b = a - b;
a = a - b;

异或取值

a ^= b;
b ^= a;
a ^= b;

[OldSixLi]

分享个新鲜的用法

let a = 0;
let b = 1;
a = [b, b = a][0];
console.log(a, b);

[xiaoqiangz]

es6 解构 [a,b] = [b,a]

[wyy-g]

ES6解构赋值 [a, b] = [b, a]; ES5 a = a + b; b = a - b; a = a - b;