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Published 20 hours ago • verified publisher icon graphql-python

python 3.5.3 SyntaxError: invalid syntax

Open dmitrii-sim opened this issue 5 years ago • 1 comments

https://github.com/graphql-python/aiohttp-graphql/blob/a7aa6c6c1e9bda5842591b2a91ad800408a21b36/aiohttp_graphql/graphqlview.py#L39

Hi! I'm using python 3.5.3. This line cause SyntaxError: invalid syntax exception because of trailing comma. I think it should be removed for compatibility with older python versions. Thank you!

dmitrii-sim avatar Jun 22 '20 09:06 dmitrii-sim

+1 Python 3.5.6

zzkate avatar Jun 30 '20 09:06 zzkate