json_model
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Generate model class from Json file. 一行命令,通过Json文件生成Dart Model类。
> pub run json_model src=json_files dist=data # 输出目录为 lib/data 大佬还更新不?😂 感觉很久没有更新啊?什么情况,莫非有更好package了吗?
依赖报错
Because github_client_app depends on json_model ^0.0.2 which depends on json_serializable ^2.0.0, json_serializable ^2.0.0 is required.
1、pubspec.yaml中添加依赖为: dependencies: json_annotation: ^2.0.0 --- 版本号必须是2.0.0 dev_dependencies: flutter_test: sdk: flutter json_model: ^0.0.2 build_runner: ^1.0.0 --- 版本号必须是1.0.0 json_serializable: ^2.0.0 --- 版本号必须是2.0.0 在Terminal中运行 flutter packages pub run json_model ,若不成功,再看下一步。 2、(1) 运行Flutter Clean,点击...
{ "code": 0, "data": "Value", "message": "string", "status": "success" } 后台一般返回这种样式,data有多种类型,怎样修改json的data可以让生产的model是任意类型dynamic,或者生产的model可以是泛型的
### json代码示例 ``` { "data":[ { "desc":"Android高级进阶直播课免费学习", "id":22, "imagePath":"https://wanandroid.com/blogimgs/fbed8f14-1043-4a43-a7ee-0651996f7c49.jpeg", "isVisible":1, "order":0, "title":"Android高级进阶直播课免费学习", "type":0, "url":"https://url.163.com/4bj" }, { "desc":"一起来做个App吧", "id":10, "imagePath":"https://www.wanandroid.com/blogimgs/50c115c2-cf6c-4802-aa7b-a4334de444cd.png", "isVisible":1, "order":2, "title":"一起来做个App吧", "type":0, "url":"http://www.wanandroid.com/blog/show/2" }, { "desc":"", "id":4, "imagePath":"https://www.wanandroid.com/blogimgs/ab17e8f9-6b79-450b-8079-0f2287eb6f0f.png", "isVisible":1,...
以下是我修改的`mo.dart`,有############的地方是修改过的 ``` import 'dart:convert'; import 'dart:io'; import 'package:path/path.dart' as path; const TAG = "\$"; const SRC = "./json"; //JSON 目录 const DIST = "lib/models/"; //输出model目录 void walk() { //遍历JSON目录生成模板 var...
Hi there, So, I have a JSON like this ``` { "groups": { "1": { "members": { "1": { "id": "1", "groupId": "1" } } }, "2": { "members": {...
引入了最新版本的json_model和json_serializable,进行get dependencies出错:  Because json_model 0.0.2 depends on json_serializable ^2.0.0 and no versions of json_model match >0.0.2
When adding the core types String or int, they must not be specified, but rather an example int or String should be written. Although the provided example shows that, it's...