break-the-ice-with-python
break-the-ice-with-python copied to clipboard
Published
20 hours ago •
darkprinx
darkprinx
Q14 Improved Solution
Each letter and digit we use has a corresponding unique Unicode integer value. We can get this value using Python's built-in ord() function. Knowing which integers represent upper- and lower-case letters, which represent the digits 0 through 9 we can then use the len() function and list comprehension to determine the number of letters and digits. My solution avoids unwieldy if else conditions etc.
Thoughts?
def count_ld(x): return print(f'LETTERS {len([v for v in x if ord(v) in range(65, 91) or ord(v) in range(97,123)])}\nDIGIT {len([v for v in x if ord(v) in range(48,54)])}')
count_ld(input("ENTER: "))
