fast-mutex
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chieffancypants
Violation of MIT license?
I noticed this code https://github.com/chieffancypants/fast-mutex/blob/master/dist/fast-mutex.js#L580-L703
is identical with this code https://github.com/thevtm/ms/blob/3d1e2b710314595596d5212639df419cfd860cb4/index.js
Did you copy without complying with the license from that thevtm/ms? Or is there another source? In any case this is quick to remedy as you only have to add the license below your own license.
Let me know if you have any questions.
Just thought you should know as we in the open source community benefit from treating other peoples licenses with outmost respect :) Cheers!
Fast-mutex is under ISC license, which as per github is:
A permissive license lets people do anything with your code with proper attribution and without warranty. The ISC license is functionally equivalent to the BSD 2-Clause and MIT licenses, removing some language that is no longer necessary.
What's the purpose of this issue?
The author of this library have copied code from another repository without respecting the license. Their MIT license is pretty clear here
The above copyright notice and this permission notice shall be included in all copies or substantial portions of the Software.
I don't see the MIT license. I'm opening a pull request.
Hi there. I'm getting back into some open source work and finally getting around to this.
The dist folder is the compiled / concatenated output of this library, and all other libraries it depends upon. I have no idea how you recognized that code, but you are indeed correct, it is from the ms package, which is depended upon by the debug package.
In other words, this is not part of my source code which is why it's not listed in the license.
