MethodOfLines.jl
MethodOfLines.jl copied to clipboard
Mixed differentials
Do I understand correctly that right now it's not possible to use second order mixed derivatives when defining the equation to solve but one has to introduce an auxiliary variable?
If I modify slightly the Brusselator example as this:
using ModelingToolkit, MethodOfLines, OrdinaryDiffEq
@parameters x y t
@variables u(..) v(..)
Dt = Differential(t)
Dx = Differential(x)
Dy = Differential(y)
Dxx = Differential(x)^2
Dyy = Differential(y)^2
# MIXED DIFFERENTIAL
Dxy = Differential(x)*Differential(y)
∇²(u) = Dxx(u) + Dyy(u) + Dxy(u)
brusselator_f(x, y, t) = (((x-0.3)^2 + (y-0.6)^2) <= 0.1^2) * (t >= 1.1) * 5.
x_min = y_min = t_min = 0.0
x_max = y_max = 1.0
t_max = 11.5
α = 10.
u0(x,y,t) = 22(y*(1-y))^(3/2)
v0(x,y,t) = 27(x*(1-x))^(3/2)
eq = [Dt(u(x,y,t)) ~ 1. + v(x,y,t)*u(x,y,t)^2 - 4.4*u(x,y,t) + α*∇²(u(x,y,t)) + brusselator_f(x, y, t),
Dt(v(x,y,t)) ~ 3.4*u(x,y,t) - v(x,y,t)*u(x,y,t)^2 + α*∇²(v(x,y,t))]
domains = [x ∈ Interval(x_min, x_max),
y ∈ Interval(y_min, y_max),
t ∈ Interval(t_min, t_max)]
# Periodic BCs
bcs = [u(x,y,0) ~ u0(x,y,0),
u(0,y,t) ~ u(1,y,t),
u(x,0,t) ~ u(x,1,t),
v(x,y,0) ~ v0(x,y,0),
v(0,y,t) ~ v(1,y,t),
v(x,0,t) ~ v(x,1,t)]
@named pdesys = PDESystem(eq,bcs,domains,[x,y,t],[u(x,y,t),v(x,y,t)])
N = 32
dx = (x_max-x_min)/N
dy = (y_max-y_min)/N
order = 2
discretization = MOLFiniteDifference([x=>dx, y=>dy], t, approx_order=order, grid_align=center_align)
# Convert the PDE problem into an ODE problem
prob = discretize(pdesys,discretization)
I get the following error:
ERROR: MethodError: no method matching collect_ivs_from_nested_operator!(::Set{Any}, ::SymbolicUtils.Add{Real, Int64, Dict{Any, Number}, Nothing}, ::Type{Differential})
Closest candidates are:
collect_ivs_from_nested_operator!(::Any, ::Term, ::Any)
Thinking about it there is no way to get them to discretize at present, sorry. I will add this to known limitations. We can eventually support this, but don't expect it until after v1.0.
Though I invite you to try an auxiliary variable.
Wait, can't I just add a new unknown function that represents the first derivative wrt one of the state space variables, and add an equation for it?
Actually yes, good point! Let me know if that works.
I fell into the same issue. Trying to see if a workaround with auxiliary variables can work.
#145 related