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Published
20 hours ago •
Purus
Purus
Removing the toast
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The toast is not necessary. Besides that, since it shows a message written in English, it can be rather confusing for users if the app is presented in other languages.
@Purus what do you think about this change? Maybe we could use the already existing writeReview flag to control showing the toast in case you don't want to remove it completely?
@KeithBacalso I moved away from this plugin as implementation is quite easy. You need:
the flutter part
static const platform = const MethodChannel('your.channel.name');
platform.invokeMethod('yourMethodName', {'android_id': 'com.yourapp', 'ios_id':'123'});
the Android part (MainActivity.kt)
class MainActivity : FlutterActivity() {
private val CHANNEL = "your.channel.name"
override fun configureFlutterEngine(@NonNull flutterEngine: FlutterEngine) {
super.configureFlutterEngine(flutterEngine)
MethodChannel(flutterEngine.dartExecutor.binaryMessenger, CHANNEL).setMethodCallHandler { call, result ->
if (call.method == "yourMethodName" && call.hasArgument("android_id")) {
val id = call.argument<String>("android_id")
val uri = Uri.parse("https://play.google.com/store/apps/details?id=$id")
context.startActivity(Intent(ACTION_VIEW, uri))
} else {
result.notImplemented()
}
}
}
}
the iOS part (in AppDelegate.swift)
@UIApplicationMain
@objc class AppDelegate: FlutterAppDelegate {
override func application(
_ application: UIApplication,
didFinishLaunchingWithOptions launchOptions: [UIApplication.LaunchOptionsKey: Any]?) -> Bool {
let controller : FlutterViewController = window?.rootViewController as! FlutterViewController
let flutterMethodChannel = FlutterMethodChannel(name: "your.channel.name", binaryMessenger: controller.binaryMessenger)
flutterMethodChannel.setMethodCallHandler({
[weak self] (call: FlutterMethodCall, result: FlutterResult) -> Void in
guard call.method == "yourMethodName" else {
result(FlutterMethodNotImplemented)
return
}
if let args = call.arguments as? [String: String] {
if let id = args["ios_id"] {
self?.openAppStore(id: id)
}
}
})
GeneratedPluginRegistrant.register(with: self)
return super.application(application, didFinishLaunchingWithOptions: launchOptions)
}
private func openAppStore(id: String) -> Void{
if let appUrl = URL(string: "https://itunes.apple.com/app/id\(id)") {
UIApplication.shared.open(appUrl, options: [:], completionHandler: nil)
}
}
}
