eslint-plugin-react-native icon indicating copy to clipboard operation
eslint-plugin-react-native copied to clipboard

no-unused-styles: false positive with variable based style object selection

Open soullivaneuh opened this issue 3 years ago • 7 comments

Considered this component having a variant prop with values white and primary, affecting the selection of the styles object:

import React, { FC } from 'react';
import {
  StyleSheet, KeyboardAvoidingView, Platform, View,
} from 'react-native';
import { SafeAreaView } from 'react-native-safe-area-context';
import { colors } from '@company/design';
import Constants from 'expo-constants';

interface Props {
  logonScreen?: boolean;
  variant?: 'white' | 'primary';
}

const styles = StyleSheet.create({
  safeArea: {
    flex: 1,
    backgroundColor: colors.white,
  },
  safeAreaLogon: {
    backgroundColor: 'white',
  },
  container: {
    flex: 1,
  },
  center: {
    justifyContent: 'center',
  },
});

const variants = {
  white: StyleSheet.create({
    container: {
      backgroundColor: 'white',
    },
  }),
  primary: StyleSheet.create({
    container: {
      backgroundColor: colors.primary,
    },
  }),
};

export const ScreenWrapper: FC<Props> = ({
  logonScreen, children, variant,
}) => {
  const variantStyle = variants[variant || 'white'];
  const viewStyle = [
    styles.container,
    variantStyle.container,
    ...logonScreen ? [styles.center] : [],
  ];

  return (
    <SafeAreaView
      style={[
        styles.safeArea,
        ...logonScreen ? [styles.safeAreaLogon] : [],
      ]}
    >
      <View style={viewStyle}>
        {
          Platform.OS === 'ios'
            ? (
              <KeyboardAvoidingView
                style={{ flex: 1 }}
                behavior="padding"
                keyboardVerticalOffset={Constants.statusBarHeight}
              >
                {children}
              </KeyboardAvoidingView>
            )
            : children
        }
      </View>
    </SafeAreaView>
  );
};

export default null;

ESlint will complain with the following:

error  Unused style detected: undefined.container  react-native/no-unused-styles

Maybe related to #125.

soullivaneuh avatar Sep 09 '22 17:09 soullivaneuh

I guess you have bad styles architecture.

What is the purpose of creating two different styles?

const variants = {
  white: StyleSheet.create({
    container: {
      backgroundColor: 'white',
    },
  }),
  primary: StyleSheet.create({
    container: {
      backgroundColor: colors.primary,
    },
  }),
};

It would be better when it would be inside main styles declaration. Or if you really want dynamic creation it can be like this:

  const viewStyle = [
    styles.container,
    {
      backgroundColor: variant === 'white' ? 'white' : colors.primary
    },
    ...logonScreen ? [styles.center] : [],
  ];

Romick2005 avatar Sep 20 '22 12:09 Romick2005

I'm having the same issue. Variant styles are accessed using bracket notation, but the linter doesn't understand it.

I guess you have bad styles architecture.

That's not a very helpful comment. What's bad about it?

AdamGerthel avatar Jan 09 '24 13:01 AdamGerthel

I'm having the same issue. Variant styles are accessed using bracket notation, but the linter doesn't understand it.

I guess you have bad styles architecture.

That's not a very helpful comment. What's bad about it?

But I described in my comment that having multiple Styles.createStylesheet is not very convenient.

What is the point having multiple styles objects not within main style object?

Romick2005 avatar Jan 09 '24 13:01 Romick2005

I'm having the same issue. Variant styles are accessed using bracket notation, but the linter doesn't understand it.

I guess you have bad styles architecture.

That's not a very helpful comment. What's bad about it?

But I described in my comment that having multiple Styles.createStylesheet is not very convenient.

Not really. You said:

It would be better when it would be inside main styles declaration.

But what's "better" about it? Having an object with multiple properties, where each key is the name and each value is a style makes sense IMO when you have a lot of style changes from variant to variant. It makes it very easy to see the differences between each variant.

Let's say we have 5 variants and each variant has 3 style properties (i.e. backgroundColor, borderWidth etc). Using your suggestion that would quickly become unmanageable. Ternary operators will be super messy, and it would require at least 5 lines in the array of styles rather than just 1 line when using bracket notation.

AdamGerthel avatar Jan 09 '24 13:01 AdamGerthel

Yeah that is your option. Could you please provide short example and I will edit it how I see it. Just to see smth

Romick2005 avatar Jan 09 '24 14:01 Romick2005

Yeah that is your option. Could you please provide short example and I will edit it how I see it. Just to see smth

Here you go: https://snack.expo.dev/jjL9yJ3ze

AdamGerthel avatar Jan 09 '24 14:01 AdamGerthel

Yeah that is your option. Could you please provide short example and I will edit it how I see it. Just to see smth

Here you go: https://snack.expo.dev/jjL9yJ3ze

I would go with theme for your case, but it could also be done like this: https://snack.expo.dev/@romick/variants

Pros: render code is cleaner, no array merge styles logic, all possible styles are cached and is not recreated on every render. Easy to change any style without no changes to break other variant style. All styles within createStylesheet is processed by the linter. Cons: duplicated styles in some style object that can cause difficulties in adding some style for each variant style.

Romick2005 avatar Jan 09 '24 17:01 Romick2005