Is there a way to provide arguments?

Open coder-mike opened this issue 4 years ago • 1 comments

The .NET equivalent XSLT transformer allows you to provide arguments to satisfy <xsl:param name="..."> in the XSLT doc.

public void Transform(System.Xml.XmlReader input, System.Xml.Xsl.XsltArgumentList? arguments, System.IO.TextWriter results);

I'm wondering if there's any equivalent with xslt-processor or a work-around?

Mar 04 '21 06:03 coder-mike

I also want to know?

You, could, in theory, force them into your xml before processing..but shouldn't have to

Dec 15 '21 07:12 ForbiddenEra