Group can exclude option, but not the reverse

[BMBurstein]

As far as I can tell, exclude() is a symmetric operation, i.e. opt1->exclude(opt2); is the same as opt2->exclude(opt1);. With options this works well, since I can call exclude() on either of the options and pass the other as a parameter. But if I have an option and a group the are mutually exclusive, I can only do the call from the group side, i.e. grp1->exclude(opt1); works, but opt1->exclude(grp1); doesn't compile.

Maybe an overload should be added to allow this to work in both directions.

[phlptp]

I do not believe this would be possible or wise as it would require circular definitions.
The recommendation to achieve the same effect is to put opt1 in a second option_group and use

grp2->exclude(grp1)

[phlptp]

Going to close this as there is an intended means to achieve the same effect and adding this suggestion would add significant complexity to the option handing code.